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4^3-11x^2-20x=0
We add all the numbers together, and all the variables
-11x^2-20x+64=0
a = -11; b = -20; c = +64;
Δ = b2-4ac
Δ = -202-4·(-11)·64
Δ = 3216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3216}=\sqrt{16*201}=\sqrt{16}*\sqrt{201}=4\sqrt{201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{201}}{2*-11}=\frac{20-4\sqrt{201}}{-22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{201}}{2*-11}=\frac{20+4\sqrt{201}}{-22} $
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